A boat leaves a dock at 9:00 pm and travels due south at a speed of 20 km/h. another boat has been heading due east at 15 km/h and reaches the same dock at 10:00 pm how many minutes after 9:00 pm were the two boats closest together? round your answer to the nearest minute.

Respuesta :

 after 9:00 P.M. 24 minutes boats were closet together.

Converting speed into km/min
20/60 = (1/3) km/min
15/60 = (1/4) km/min 

first boat distance from the dock is d=1/3 km each minute
Second boat distance from the dock reduced by each minute is
D = 15 - (1/4) * t 

d^2 + D^2 
= (1/9) * t^2 + (15 - 1/4 * t) ^2 
= (1/9) * t^2 + 225 - (30/4) *t + (1/16) t^2 

After derivation we get
t=24 minutes