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The figure below shows three uniform objects: a rod with m1 = 7.00 kg, a right triangle with m2 = 3.70 kg, and a square with m3 = 5.30 kg. their coordinates in meters are given. determine the center of gravity for the three-object system.

Respuesta :

Nirina7
the answer is 

G = [m1(veca1a2) + m2 (veca3a4) + m3veca5a6)] /  (m1 + m2  + m3) 

G= m1x5 + m2 x 4sqrt (2) + m3x 3sqrt (2)  / 16  =  35 +4 x 3.7x sqrt (2) + 5.3 x3 4sqrt (2) / 16 =35 + 36 sqrt (2) / 16
G = 53.09
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