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Given a spring which has been compressed by 16.08 m and has a spring constant of 7.7 N/m. What potential energy will it have in Joules?

Respuesta :

AL2006

The elastic potential energy stored in a spring is

                         (1/2) (spring constant) (distance of stretch)²

                 =      (1/2) (7.7 N/m) (16.08 m)²

                 =       (3.85  N/m) (258.57 m²)

                 =            995.5  N-m

                 =           995.5  joules 

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