Respuesta :

Simple....

you have: [tex]2\ \textless \ 2n+20 \leq 4[/tex]

--->>>What you want to do is move all the terms not containing n from the center section of the interval inequality-->>>

[tex]-9\ \textless \ n \leq -8[/tex]

On the graph it starts with the circle point filled in at -8(*****) and a circle unfilled at -9(°°°°°°).

Thus, your answer.
To solve this compound inequality, solve 2 < 2n + 20.
You should get -9 < n   (n > -9)

Then solve the right side of the compound inequality 2n + 20 <= 4.
You should be n<= -8

When you graph this on the number line, you put an open dot on the -9 and a closed dot on the -8 and connect the two points with a line.  That mean n is greater than -9 and less than or equal to -8.


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