If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentum at this instant?

Respuesta :

 The rate of chage of angular momentum = the net torque on the object. 
The net torque is the weight "mg" times the perpendicular distance from the line of action of the weight to the origin, x 
dL/dt = mgx = mgrCos(36.8) 

Or it is the component of the weight perpendicular to the position vector, mgCos(36.8) , times the magnitude of the position vector, r ; 
dL/dt = {mgCos(36.8}]r 

Obviously the same eq. 
Everything is given, so just plug in the values. The particle velocity is not needed to find rate of change of L.