Answer:
1.05 × 10 ∧15 Hz.
Explanation:
The minimum amount of energy of photon E = 6.94×10∧-19 J
The value of Plank's constant , h = 6.626 × 10∧-34 J s
So the minimum frequency of light necessary to emit electrons from titanium via photoelectric effect , E = h . ν
where ν is the frequency
ν = E / h
ν = 6.94×10∧-19 J / 6.626 × 10∧-34 J s
= 1.05 × 10 ∧15 / s
= 1.05 × 10 ∧15 Hz.
The minimum frequency of light necessary to emit electrons from titanium via the photo electric effect is; f = 1.05 × 10¹⁵ Hz.
The minimum amount of energy of a photon required for titanium to emit an electron is denoted by, E whose value is;
The Planck's constant is given as,
The frequency of light required is given as; f = ?
However, the three quantities are related according to the equation:
By dividing both sides of the equation by 6.626 × 10-³⁴; we have;
Ultimately, the frequency of light required is: f = 1.05 × 10¹⁵ Hz
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