Answer:
Option A is correct.
x =4 , y = 2
Explanation:
Given the system of equation:
[tex]2x+6y = 20[/tex] ......[1]
[tex]3x-2y = 8[/tex] .....[2]
Multiply equation [2] by 3 both sides we get;
[tex]3 \cdot (3x-2y) = 3 \cdot 8[/tex]
Using distributive property: [tex]a\cdot (b+c) = a\cdot b+ a\cdot c[/tex]
[tex]9x - 6y = 24[/tex] .....[3]
Add equation [1] and [3], to get eliminate y we get;
[tex]2x+6y+9x-6y= 20+24[/tex]
Combine like terms we have;
[tex]11x = 44[/tex]
Divide both sides by 11 we get;
[tex]x = 4[/tex]
Substitute the value of x =4 in [1] we get;
2(4) + 6y = 20
8 + 6y = 20
Subtract 8 from both sides we have;
6y = 12
Divide both sides by 6 we have;
y = 2
Therefore, the values of x and y are; 4 and 2.
