Respuesta :
She mightstart again, this time grouping i a different way.
For example:
Step 1: [6x^4 + 3x^2] - [8x^2 - 4]
Step 2: 3x^2 [2x^2 + 1] - 4[2x^2 - 1]
But this drives to the same conclusion.
She could yet try other ways like adding the like terms to get: 6x^4 - 5x^2 + 4
and make a change of variable x^2 = y=> 6y^2 - 5y + 4 and now use the quadratic formula to find the roots.
This method will tell without doubts that there are not roots and the polynomial cannot be factored. So, the GCF is 1.
For example:
Step 1: [6x^4 + 3x^2] - [8x^2 - 4]
Step 2: 3x^2 [2x^2 + 1] - 4[2x^2 - 1]
But this drives to the same conclusion.
She could yet try other ways like adding the like terms to get: 6x^4 - 5x^2 + 4
and make a change of variable x^2 = y=> 6y^2 - 5y + 4 and now use the quadratic formula to find the roots.
This method will tell without doubts that there are not roots and the polynomial cannot be factored. So, the GCF is 1.
Answer:
B. Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).
Step-by-step explanation:
I guessed it and got this as the answer