Answer:
The quantity of moles in 131.50g of Zn(NO3)2 is 0.6943
Explanation:
Using the equation:
Moles = mass/ molecular mass
Moles Zn(NO3)2 = mass Zn(NO3)2 / molecular mass Zn(NO3)2
mass Zn(NO3)2 = 131.50g
molecular mass Zn(NO3)2 is calculated by looking at the atomic mass of each element in the periodic table, then multiplying by the number on the compound's formula:
Zn= 65.38 g/mol
N= 14 g/mol
O= 16 g/mol
molecular mass Zn(NO3)2 = Zn + 2*N + 2*3*O =65.38 + (2*14) + (2*3*16)
molecular mass Zn(NO3)2 = 189,38 g/mol
Moles Zn(NO3)2 = 131.50g / 189,38 g/mol
Moles Zn(NO3)2 = 0.6943
