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Matthew is waterskiing. As the boat starts moving, he is at an angle of 8.0Á to the right of the boat. The boat applies 250 newtons over the first 50 meters, while the angle stays at roughly 8.0Á. What work has the boat done on Matthew

Respuesta :

F = 250

d = 50

[tex]\theta=8^o[/tex]

workdone=Fd*cos([tex]\theta[/tex]) =250*50*cos([tex]8^o[/tex]) =12500*cos([tex]8^o[/tex])=12378.35 joule

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artiztyoung

Answer:

B : 1.2 x 10^4 joules

Step-by-step explanation:

For edmentum/pluto

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