Respuesta :
y = -2x^2 + 50x + 300
-2x^2 + 50x + 300 ≥ 300
-2x^2 + 50x ≥ 0
-2x^2 ≥ -50x
x^2 ≤ 25x
x ≤ 25
Therefore, required domain is 0 ≤ x ≤ 25
-2x^2 + 50x + 300 ≥ 300
-2x^2 + 50x ≥ 0
-2x^2 ≥ -50x
x^2 ≤ 25x
x ≤ 25
Therefore, required domain is 0 ≤ x ≤ 25
Answer:
The domain of the function so that the function is at least 300 is:
0 ≤ x ≤ 25
Step-by-step explanation:
We are given graph of the function y as:
[tex]y =-2x^2+50x+300[/tex]
[tex]-2x^2+50x+300\geq 300[/tex]
on subtracting both side of the inequality by 300 we obtain:
[tex]-2x^2+50x\geq 0[/tex]
[tex]-2x(x-25)\geq 0[/tex]
This inequality is obtained when one of the term is positive and the other is negative:
i.e. if x≥0
and x-25≤0
i.e. x≤25 then the product :
-2x(x-25)≥0.
Hence, the domain is:
0 ≤ x ≤ 25