Find the indicated limit, if it exists.

limit of f of x as x approaches negative 8 where f of x equals x plus 9 when x is less than negative 8 and f of x equals negative seven minus x when x is greater than or equal to negative 8

-8
1
17
The limit does not exist.

Respuesta :

Find [tex]{\displaystyle\lim_{x \rightarrow ~-8}f(x)}[/tex]

where [tex]{ f(x) = \begin{cases} & x+9,~~~~~~~~~~{\large x\ \textless \ -8} \\ & -7-x,~~~~~~{\large x\ge-8} \end{cases} }[/tex]

So to find the left sided limit, you need to plug in -8, into x+9 and to find the right sided limit, you need to plug in -8, into -7-x.

If the two sides of the limit are no equivalent, then [tex]{\displaystyle\lim_{x \rightarrow ~-8}f(x)~~DNE}[/tex]

Since both sides are equal to 1, the limit is 1.

Answer:

1

Step-by-step explanation:

just took the test