The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i.
The length of the hypotenuse is (a-4 or b-5) units, and the area of the triangle is (a-6, b-12) square units
Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5.
Or you could use the pythagorean theorem
a² + b² = c²
3² + 4² = c²
25 = c²
c = 5 then find area A=1/2bh 1/2(3*4) 6
