Respuesta :
It contain oxygen atom calculated below
6.35gC x 2.00gO/1.50gC
= 8.47g O
The law is that a sample of a pure substance is the same as any other sample of the pure substance no matter what the source is
hope it helps
6.35gC x 2.00gO/1.50gC
= 8.47g O
The law is that a sample of a pure substance is the same as any other sample of the pure substance no matter what the source is
hope it helps
Answer:
[tex]8.467[/tex] grams of oxygen
Explanation:
The law governing this problem is "The Law of Constant Composition "
As per this law, all compounds irrespective of their origin and source have the same composition and properties in their purest form
It is a simple proportion and ratio related problem.
[tex]1.50[/tex] grams of carbon require [tex]2.0[/tex] grams of oxygen
[tex]1.0[/tex] grams of carbon will require oxygen
[tex]= \frac{2}{1.5}[/tex]
[tex]6.35[/tex] grams of carbon will require oxygen
[tex]\frac{2}{1.5}*6.35\\= 8.4666\\= 8.467[/tex]