(3,5),
(5,8),
(6,13)
------
(14,26)/3
then use the point slope form of a line to find equation of line
[tex]y-y_1=m(x-x_1)
\\y - \frac{26}{3} = 2.5(x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} (x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{5}{2}\times\frac{14}{3}
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{35}{3}
\\6y-52=15x-70
\\15x-6y-18=0[/tex]
Find y-intercept for x = 0.
[tex]15x-6y-18=0
\\15\times0-6y-18=0
\\-6y=18
\\y=-3[/tex]
