Respuesta :
[tex]y=A \cos(Bx)[/tex]
A - amplitude
[tex] \frac{2\pi}{B} [/tex] - period
[tex]y = \frac{ 1 }{ 4 } \cos \frac{ 2\pi }{ 3 } \Theta[/tex]
1. A = [tex] \frac{1}{4} [/tex]
2. [tex] \frac{2\pi}{B}=\frac{2\pi}{\frac{2\pi}{3}}= \frac{\frac{2\pi}{1}}{\frac{2\pi}{3}}= \frac{3\times2\pi}{1\times2\pi}=3 [/tex]
3. Since nothing is added or subtracted outside, the "midline" is the x axis y = 0
A - amplitude
[tex] \frac{2\pi}{B} [/tex] - period
[tex]y = \frac{ 1 }{ 4 } \cos \frac{ 2\pi }{ 3 } \Theta[/tex]
1. A = [tex] \frac{1}{4} [/tex]
2. [tex] \frac{2\pi}{B}=\frac{2\pi}{\frac{2\pi}{3}}= \frac{\frac{2\pi}{1}}{\frac{2\pi}{3}}= \frac{3\times2\pi}{1\times2\pi}=3 [/tex]
3. Since nothing is added or subtracted outside, the "midline" is the x axis y = 0
(a) The period of the sound wave is 3.0 s
(b) The amplitude of the sound wave is 1/4
(c) The equation of the midline represents x-axis.
Period of the sound wave
The period of the sound wave is calculated as follows;
y = A cos(ωt)
where;
- A is amplitude of the sound wave
- ω is angular speed
y = A cos(2π/T)
2π/T = 2π/3
T = 3
Amplitude of the wave
A = 1/4
The middle of the equation is on x - axis
Learn more about amplitude of waves here: https://brainly.com/question/19036728
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