Answer : The net ionic equation will be,
[tex]Ca^{2+}(aq)+2OH^{-}(aq)\rightarrow Ca(OH)_2(s)[/tex]
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced ionic equation will be,
[tex]2H_2O(aq)+Ca(NO_3)_2(aq)\rightarrow 2HNO_3(aq)+Ca(OH)_2(s)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]4H^+(aq)+2OH^{-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow Ca(OH)_2(s)+2H^+(aq)+2NO_3^{-}(aq)[/tex]
In this equation, [tex]H^+\text{ and }NO_3^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Ca^{2+}(aq)+2OH^{-}(aq)\rightarrow Ca(OH)_2(s)[/tex]
