Complete the electron-pushing mechanism for the e1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid.

Question

09-11-2016
Physics

contestada

Complete the electron-pushing mechanism for the e1 reaction when 2-methylbutan-2-ol is treated with 20% sulfuric acid.

Respuesta :

Otras preguntas

At this moment, however, the rooms bore every mark of having been recently and hurriedly ransacked; clothes lay about the floor, with their pockets inside out;

¿_______ es la hermana de Marcos

A tariff on a product has which of the following results? a. An increase in the prices of imports and consumers b. An increase in the demand for an imported g

The side lengths of a square are 7 in. What is the length of the diagonal?

Find the distance between the points below.

One fabric costs 15.00 for two yards. Another costs 37.50 for 5 yards. Do these fabrics have the same unit costs?

A group of students were surveyed to find out if they like working as a camp counselor and/or as a lifeguard during summer break. The results of the survey are

"Mrs. Norman enjoys playing bridge." if "playing bridge" what the gerund phrase, what does it function? A) It is an adverb modifying a verb. B) It is a noun fun

Which part of the endocrine system are the male reproductive glands? A. testes B. pancreas C. adrenal gland D. pituitary gland

The Midnight News by Jon Caswell Say good-bye to the pupfish, He’s gone and hardly missed; No one knows why he deserves it, He just no longer exists. Without kn

MissPhiladelphia MissPhiladelphia · Answer 1 · 2016-11-22T09:38:54+01:00

E1 reaction works in the mechanism that the removal of an HX substituent results in the formation of a double bond. The E1 reaction for 2-methylbutan-2-ol is shown in the figure. This reaction is called acid-catalyzed dehydration of a tertiary alcohol.

The mechanism works in three major steps:
1. The OH group of the main reactant is hydrated by H2SO4 so it becomes H2O.
2. The H2O leaves taking electrons with it. This results to a carbocation intermediate on the carbon atom where it was attached.
3. Another H2O protonates the beta carbon. This is the carbon atom next to the carbocation. It will donate its electrons to the neighboring C-C bond, as indicated by the arrow. The carbons are rehybridized from sp3 to sp2, which is a pi bond. As a result, a double bond forms.

The product is 2-methyl-2-butene.

AkshayG AkshayG · Answer 2 · 2019-11-01T10:37:45+01:00

The final production of E1 elimination of 2-methylbutan-2-ol is 2-methyl-2-butene. For the electron pushing mechanism of E1 elimination reaction refer to the image attached.

Further explanation:

E1 elimination reaction:

E1 elimination reaction is a unimolecular reaction that removes an HX leaving group and produce a double bond. The mechanism of E1 elimination involves deprotonation of hydrogen from beta carbon and formation of carbocation intermediate. Finally, the removal of leaving group takes place.

The mechanism of E1 elimination of 2-methylbutan-2-ol is as follows:

Step 1: The alcohol group on 2-methylbutan-2-ol is hydrated by [tex]{{\text{H}}_2}{\text{S}}{{\text{O}}_4}[/tex] . This makes alcohol a better leaving group.

Step 2: The leaving group leaves and takes the electrons of bond pair with itself and forms a carbocation intermediate.

Step 3: Another molecule of [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] comes and deprotonate the beta carbon and leaves an electron pair on beta carbon. The electron pair on beta carbon are donated to the carbocation carbon and formation of double bond takes place. The final product is 2-methyl-2-butene.

Learn more:

1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603

2. Determine the product formed when 2-propanol react with NaH: https://brainly.com/question/5045356

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: E1 elimination reaction

Keywords: E1 elimination reaction, 2-methylbutan-2-ol, structure of alkenes, electron-pushing mechanism, and 20% sulfuric acid.