Respuesta :
767.448 Joules of heat is required.
You use the equation Q=MCdeltaT
Make sure you convery celsius to Kelvin
Specific heat of water is 4.18
So it will be Q=2.55(4.18)(72)
Q=767.448
You use the equation Q=MCdeltaT
Make sure you convery celsius to Kelvin
Specific heat of water is 4.18
So it will be Q=2.55(4.18)(72)
Q=767.448
The amount of heat is required to convert 2.55g of water at 28.0 degree celsius to steam 100 degree celsius is 767.448 joules.
How do we calculate required heat?
The amount of heat which is absorbed or released by any substance will be calculated as:
Q = mcΔT, where
According to the question:
m = mass of water = 2.55g
c = specific heat of water = 4.18 joules
ΔT = change in temperature = 100-28 = 72degree celsius
On putting all these values on the above equation, we get
Q = (2.55)(4.18)(72) = 767.448 joules
Hence required heat is 767.448 joules.
To know more about specific heat, visit the below link:
https://brainly.com/question/16559442
