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Write the point-slope form of the line that passes through the origin and is parallel to a line with a slope of 2. Include all of your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

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y = 2x satisfies this set of regulations

Point slope form would be y - 0 = 2( x - 0 )

Answer:

[tex]y-0=2(x-0)[/tex]

Step-by-step explanation:

The point-slope form is defined as

[tex]y-y_{1} =m(x-x_{1} )[/tex]

Where [tex](x_{1},y_{1})[/tex] is a point that the line intercepts and [tex]m[/tex] is the slope.

So, in this case, the slope is 2, and the point is (0,0), because it passes through the origin.

Replacing all these values in the formula, we have

[tex]y-y_{1} =m(x-x_{1} )\\y-0=2(x-0)\\y=2x[/tex]

Therefore, the line which the given characteristics is [tex]y=2x[/tex], and its slope-form is

[tex]y-0=2(x-0)[/tex]

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