Answer:
F = 3.15 N
Explanation:
Given electric charge, q = 6.3 μC
The magnitude of electric field, [tex]E=5\times 10^5\ N/C[/tex]
We need to find the electric force on the charge due to the electric field. The electric force is given by :
F = qE
Putting all the values,
[tex]F=6.3\times 10^{-6}\times 5\times 10^5\\\\F=3.15\ N[/tex]
So, the required force on the charge is 3.15 N.
