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- The position of an object moving in a straight line
is given by s = 2t^2 - 3t, where s is in meters and t
is the time in seconds the object has been in
motion. How long (to the nearest tenth) will it
take the object to move 11 meters?


PLEASE HELP AND SHOW WORK ILL GIVE 20 PTS

Respuesta :

Answer:

s(t) = 2t^2-3t

19 = 2t^2-3t

2t^2-3t-19=0

t = [3 +- sqrt(9-4*2*-19)]/4

t = [3 +- sqrt(161)]/4

t = [3 +- 12.6886]/4

Positive answer:

t = [3+12.6886]/4

t = 3.9221 seconds

Step-by-step explanation:

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