Answer:
[tex]AC = 9cos(45)[/tex]
[tex]BC = 9 sin(45)[/tex]
Step-by-step explanation:
Given
See attachment for triangle
Required
Select the equations that solves the unknown lengths
From the attachment, the unknown lengths are:
AC and CB
Where
[tex]AB = 9[/tex]
To calculate AC, we make use of cosine rule
[tex]cos\theta = \frac{Adjacent}{Hypotenuse}[/tex]
[tex]cos(45)= \frac{AC}{9}[/tex]
Make AC the subject
[tex]AC = 9*cos(45)[/tex]
[tex]AC = 9cos(45)[/tex]
To solve for BC, we make use of sine rule
[tex]sin\theta = \frac{Opposite}{Hypotenuse}[/tex]
[tex]sin(45)= \frac{BC}{9}[/tex]
Make BC the subject
[tex]BC = 9 * sin(45)[/tex]
[tex]BC = 9 sin(45)[/tex]
