Factorise the following expression :

Answer:
The answer is "[tex](p-1) (pq-r^2)[/tex]"
Step-by-step explanation:
Given:
[tex]\to P ^2q-pr^2-pq+r^2\\\\[/tex]
Rearrange the above value:
[tex]\to P ^2q-pr^2-pq+r^2 = p^2q-pq-pr^2+r^2\\\\[/tex]
[tex]= pq(p-1)-r^2(p-1)\\\\= (p-1)(pq-r^2)\\\\[/tex]