What is the length of the line?

Answer:
[tex]\sqrt{61}[/tex]
Step-by-step explanation:
x = 6 units horizontally
y = 5 units vertically
Use the pythagorean theorem[tex]\sqrt{x^{2} + y^{2} } = L[/tex]
Plug x and y into the equation, and you will get [tex]\sqrt{61}[/tex] as the length.
Answer:
7.8 units (which is to the nearest tenth)
Step-by-step explanation:
We apply the Pythagorean Theorem here; the length of the line is the length of the hypotenuse of a triangle whose horizontal leg length is 6 and whose vertical leg length is 5 units. This Theorem is expressed symbolically as
a^2 + b^2 = c^2. In this particular case, a = 6, b = 5 and c is to be determined. Performing the calculations, we get
6^2 + 5^2 = c^2, or:
36 + 25 = 61 = c^2
Taking the positive square root of both sides, we get c = √61 ) exactly,
which rounds off to 7.8 units (to the nearest tenth).
The length of the line is 7.8 units.