trinity6883 trinity6883
  • 07-03-2021
  • Mathematics
contestada

Simplify and write the trigonometric expression in terms of sine and cosine:
(2+tan^2x/sec^2x) -1 =(f(x))^2​

Respuesta :

really226
really226 really226
  • 07-03-2021

Answer:

f(x) = + cosx or - cosx

Step-by-step explanation:

(2+tan^2x/sec^2x) -1 =(f(x))^2​

=(( 1 + sec^2x)/sec^2x) -1

= 1 / sec^2x + 1 - 1

=  1 / sec^2x

= cos^2x

(f(x))^2​ = cos^2x

f(x) = + cosx or - cosx

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