Answer:
x=9, -9
Step-by-step explanation:
Use difference of squares to the denominator.
so
[tex]\frac{x^2+4x+3}{(x+9)(x-9)}[/tex]
If you plug 9 or -9 for x, the denominator becomes 0, meaning that the value would be undefined. Thus, if would not be in the domain of g.
So, x=9, -9
