Given:
A composed figure of a rectangle, semicircle and another semicircle removed.
To find:
The area of the given figure.
Solution:
From the given figure it is clear that the diameter of semicircle and removed semicircle are same, i.e. 8 cm.
Since the diameter of semicircle are equal, therefore their area is also equal.
The area of the given figure is:
A = Area of the rectangle - Area of removed semi circle + Area of semicircle
A = Area of the rectangle - Area of semicircle + Area of semicircle
A = Area of the rectangle
We know that, the area of a rectangle is
[tex]A=length\times width[/tex]
The length of the rectangle is 14 units and width is 8 units. So, the area of composed figure is
[tex]A=14\times 8[/tex]
[tex]A=112[/tex]
Therefore, the area of the combined figure is 112 sq. units.
