from the sum of (3x2-4y2+5x) and (5-4x+2x2) subtract the sum of (-x2+2x-5) and (3y2-3x-3)

Answer and Step-by-step explanation:
Simply add the expression together, then subtract the sum of the other expression
[tex]6x^{2} - 7y^{2} + 2x + 13[/tex] is the answer.
[tex]3x^{2} - 4y^{2} + 5x + (5 - 4x + 2x^{2} )\\\\5x^{2} - 4y^{2} + x + 5\\\\\\-x^{2} + 2x - 5 + (3y^{2} - 3x - 3)\\\\\\-x^{2} + 3y^{2} - x - 8\\\\\\5x^{2} - 4y^{2} + x + 5 - (-x^{2} + 3y^{2} - x - 8)\\\\\\\\\\5x^{2} - 4y^{2} + x + 5 + x^{2} - 3y^{2} + x + 8\\\\\\\\\\\\6x^{2} - 7y^{2} + 2x + 13[/tex]
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