How many moles of PbCl2 are produced
if 14 moles of AlCl3 are consumed?
3Pb(NO3)2 + 2AlCl3 + 3PbCl2 + 2A1(NO3)3

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kampadu049 kampadu049 · Answer 1 · 2021-03-07T20:02:21+01:00

Answer:21 moles of PbCl2 formed

Explanation: 3Pb(NO3)2(aq) + 2AlCl3(aq) --> 3PbCl2(s) + 2Al(NO3)3(aq)

14 moles AlCl3 x 3 moles PbCl2/2 moles AlCl3 =21 moles of PbCl2 formed

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Eduard22sly Eduard22sly · Answer 2 · 2022-04-21T12:25:15+02:00

The number of moles of PbCl₂ produced when 14 moles of AlCl₃ are consumed in the reaction is 21 moles

3Pb(NO₃)₂ + 2AlCl₃ —> 3PbCl₂ + 2Al(NO₃)₃

From the balanced equation above,

2 moles of AlCl₃ reacted to produce 3 moles of PbCl₂.

From the balanced equation above,

2 moles of AlCl₃ reacted to produce 3 moles of PbCl₂.

Therefore,

14 moles of AlCl₃ will react to produce = (14 × 3) / 2 = 21 moles of PbCl₂.

Thus, 21 moles of PbCl₂ were obtained from the reaction.

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