Respuesta :
First u would use the slope formula : (y2 - y1) / (x2 - x1) to find the slope.
You would then use y = mx + b formula......sub in ur slope for m...and u would sub in one set of ur points (x,y), it does not matter which set of points u use.
You would then solve for b, ur y int.
Example : (1,2)(3,4)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (4 - 2) / (3 - 1) = 2/1 or just 2
y = mx + b
slope(m) = 2
use either of ur points (1,2)...x = 1 and y = 2
now sub and find b
2 = 2(1) + b
2 = 2 + b
2 - 2 = b
0 = b
so ur equation is : y = 2x + 0....or just y = 2x
You would then use y = mx + b formula......sub in ur slope for m...and u would sub in one set of ur points (x,y), it does not matter which set of points u use.
You would then solve for b, ur y int.
Example : (1,2)(3,4)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (4 - 2) / (3 - 1) = 2/1 or just 2
y = mx + b
slope(m) = 2
use either of ur points (1,2)...x = 1 and y = 2
now sub and find b
2 = 2(1) + b
2 = 2 + b
2 - 2 = b
0 = b
so ur equation is : y = 2x + 0....or just y = 2x
Given the two points [tex] (x_{1},y_{1}) [/tex] and [tex] (x_{2},y_{2}) [/tex], we are going to use the slope formula, [tex] m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex], to find the slope of the line passing throughout our two points; then, we are going to replace the values in the point slope formula, [tex] y=m(x-x_{1})+y_{1} [/tex], and simplify to complete the equation of our line.
Let's check this out with an example:
suppose you have the points (1,5) and (3,8), so [tex] x_{1}=1 [/tex], [tex] y_{1}=5 [/tex], [tex] x_{2}=3 [/tex], and [tex] y_{2}=8 [/tex].
First, we are going to use the slope formula to find the slope of the line passing throughout our two points:
[tex] m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex]
[tex] m=\frac{8-5}{3-1} [/tex]
[tex] m=\frac{3}{2} [/tex]
Now that we have the slope of our line, we can use the point slope formula to complete our line equation:
[tex] y=m(x-x_{1})+y_{1} [/tex]
[tex] y=\frac{3}{2}(x-1)+5 [/tex]
[tex] y=\frac{3}{2} x-\frac{3}{2} +5 [/tex]
[tex] y=\frac{3}{2} x+\frac{7}{2} [/tex]