Answer:
(a) The output is -1
(b) The output is 32
Explanation:
Given: The above code
Solving (a): The output when 1, 1 and 1 is passed to the function
From the question, we have: print(mystery(x))
This means that only the value of x (which in this case is 1) will be passed to the mystery function
(a, b = 8, c = -6) will then be seen as: (a = 1, b = 8, c = -6)
[tex]2 * b + a + 3 * c = 2 * 8 + 1 + 3 * -6[/tex]
[tex]2 * b + a + 3 * c = -1[/tex]
The output is -1
Solving (b): The output when 8, 6 and 4 is passed to the function
From the question, we have: print(mystery(x,y,z))
This means that values passed to the function are: x = 8, y = 6 and z = 4
(a, b = 8, c = -6) will then be seen as: (a = 8, b = 6, c = 4)
[tex]2 * b + a + 3 * c = 2 * 6 + 8 + 3 * 4[/tex]
[tex]2 * b + a + 3 * c = 32[/tex]
The output is 32
If we add the line of code print(mystery(x)) and our input are 1, 1 and 1 the output will be -1.
If we add the line of code print(mystery(x, y, z)) and our inputs are 8, 6 and 4 the out put will be 32.
This is the python code:
def mystery(a, b = 8, c = -6):
return 2 * b + a + 3 * c
#MAIN
x = int(input("First value: "))
y = int(input("Second value: "))
z = int(input("Third value: "))
print(mystery(x))
#What is output when the user enters 1, 1, and 1?
#Suppose we add the following line of code to our program:
print(mystery(x, y, z))
#What is output when the user enters 8, 6, and 4?
The code is written in python
The first print statement with the input as 1, 1 and 1 will return -1
The second print statement with the input 8, 6 and 4 will return 32.
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