Respuesta :

dsdrajlin

Answer:

0.559 L

Explanation:

Step 1: Given data

  • Moles of sodium iodide (n): 0.405 mol
  • Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

V = n/M

V = 0.405 mol/(0.724 mol/L) = 0.559 L

samueladesida43

The volume in Litres of a 0.724 M Nal solution that contains 0.405 mol of Nal is 0.56L.

HOW TO CALCULATE VOLUME:

  • The volume of a solution can be calculated by dividing the number of moles by the molarity as follows:

  • Volume = no. of moles ÷ molarity

  • According to this question, 0.724 M sodium iodide (NaI) solution contains 0.405 mol of Nal, the volume can be calculated as follows:

  • Volume = 0.405mol ÷ 0.724M

  • Volume = 0.56 Litres

  • Therefore, the volume in Litres of a 0.724 M Nal solution that contains 0.405 mol of Nal is 0.56L.

Learn more at: https://brainly.com/question/15626439?referrer=searchResults

Otras preguntas