dattimusaumar
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a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?​

Respuesta :

hamzaahmeds

Answer:

L = 2 J.s

Explanation:

The angular momentum of an object travelling in a horizontal circle is given by the following formula:

[tex]L = mvr[/tex]

where,

L = Angular momentum = ?

m = mass = 0.8 kg

v = linear speed = rω

r = radius of circular path = length of rope = 0.5 m

ω = Angular Speed = 10 rad/s

therefore,

[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]

L = 2 J.s

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