Answer:
θ = -60.94°
Step-by-step explanation:
The given vector is:
v = -5i+9j
We need to find the angle of this vector.
The angle of this vector form is given by :
[tex]\tan\theta=\dfrac{y}{x}\\\\\tan\theta=\dfrac{9}{-5}\\\\\tan\theta=-1.8\\\\\theta=\tan^{-1}(-1.8)\\\\=-60.94^{\circ}[/tex]
So, the angle of this vector is -60.94°.
