Answer:
Step-by-step explanation:
[tex]\text{This experiment is a binomial experiment}}[/tex]
[tex]\text{ The outcome of general = 0.35}[/tex]
[tex]So; If[/tex] [tex]X \sim Binomial (n = 3,p= 0.35)[/tex]
[tex]Then;[/tex]
[tex]Mean,[/tex] [tex]E(X) = np[/tex]
[tex]E(X) = (3)(0.35) \\ \\ E(X) = 1.05[/tex]
[tex]\text{Standard deviation:}[/tex]
[tex]\sigma= \sqrt{np(1-p)} \\ \\ = \sqrt{(3)(0.35)(1-0.35)} \\ \\ =0.826[/tex]
[tex]Thus;[/tex]
[tex]\text{Let X be the number of card selections with outcome "General."}[/tex]
[tex]\mathbf{ Then \ X \ is \ a\ binomial \ random \ variable \ with \ mean \ E(X) \ = \ 1.05}[/tex]
[tex]\mathbf{and \ standard \ deviation = 0.826}[/tex]