The number of atoms present in 591 g of gold is 1.81×10²⁴ atoms
From Avogadro's hypothesis,
1 mole of Gold = 6.02×10²³ atoms
But
1 mole of gold = 197 g
Thus,
197 g of gold = 6.02×10²³ atoms
197 g of gold = 6.02×10²³ atoms
Therefore,
591 g of gold = (591 × 6.02×10²³) / 197
591 g of gold = 1.81×10²⁴ atoms
Thus, 1.81×10²⁴ atoms is present in 591 g of gold.
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