The end of the stencil located when the beginning of the left edge is provided so it should be (9,3).
Calculation of the end of the stencil located:
The given line should be divided in the ratio 1:3 and the coordinate of the point P where the line is divided is (3,0).
So,
Given a line from [tex](x_1,y_1) \: to\: (x_2,y_2)[/tex] that is divided in the ratio m:n,
Now the coordinates of the point P of division should be derived by the below formula:
[tex]P(x,y)=\left(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n}\right)[/tex]
Since
P(x,y)=(3,0)
m:n=1:3
[tex](x_1,y_1)[/tex] =(1,-1)
So,
[tex](3,0)=\left(\dfrac{1x_2+3(1)}{3+1} ,\dfrac{1y_2+3(-1)}{3+1}\right)\\\\\dfrac{1x_2+3(1)}{3+1}=3\\x_2+3=3*4\\x_2=12-3=9\\\dfrac{1y_2+3(-1)}{3+1}=0\\y_2-3=0*4\\y_2=3+0=3[/tex]
hence, The end of the stencil located when the beginning of the left edge is provided so it should be (9,3).
learn more about edge here: https://brainly.com/question/17337252
