When there is change of position of an object in any direction, the rate of such change is termed as speed. Speed can be measured as the ratio of distance covered to time taken to cover that distance. The formula for speed is:
[tex]\rm Speed = \dfrac{\rm Distance}{\rm Time}[/tex]
For the given question, the speed of the bugs is [tex]\rm 4\: inch/s[/tex] and [tex]\rm 6\: inch/s[/tex].
Calculations:
Given:
Speed of bug in the east is [tex]\rm 2\:inch/s[/tex] more than the bug running in south.
Let the speed of first bug be [tex]\rm x[/tex]
Then the speed of second bug is [tex]\rm x + 2[/tex]
Time taken is 1 second
and distance covered is 10 inches
We know that :
[tex]\rm Speed = \dfrac{\rm Distance}{\rm Time}\\[/tex]
[tex]\begin{aligned} \rm Total\:speed \:of\:both\:bugs &= x + (x + 2)\\&= 2x + 2\end[/tex]
Therefore,
[tex]\begin{aligned} \rm 2x + 2 &=\dfrac{10}{1 } \\\\2x + 2 &= 10\\\\2x &= 10 - 2\\\\2x &= 8\\\\x &= \dfrac{8}{2}\\\\x &= 4\end[/tex]
Hence the speed of first bug is [tex]4\: \rm inch/s[/tex] and the speed of second bug is [tex]\rm 6\: inch/s[/tex].
Learn more about speed here:
https://brainly.com/question/7359669
