Answer:
[tex]v = 22.54m/s[/tex] --- Velocity
[tex]h = 25.921m[/tex] --- Distance
Explanation:
Given
[tex]u = 0m/s[/tex] --- Initial velocity
Solving (a): Velocity after 2.3s
To do this, we use the first equation of motion
[tex]v = u + at[/tex]
Where
[tex]t = 2.3s[/tex]
[tex]a = g = 9.8m/s^2[/tex]
So, the equation becomes:
[tex]v = 0 + 9.8 * 2.3[/tex]
[tex]v = 0 + 22.54[/tex]
[tex]v = 22.54m/s[/tex]
Solving (b): Distance covered in 2.3s
We make use of:
[tex]h = ut + \frac{1}{2}gt^2[/tex]
This gives:
[tex]h = 0 * 2.3 + \frac{1}{2}*9.8 * 2.3^2[/tex]
[tex]h = \frac{1}{2}*9.8 * 5.29[/tex]
[tex]h = 25.921m[/tex]
