Which change in this process would shift the equilibrium to produce the
maximum possible NH3?
3H2 + N2 2 2NH3 + energy
A. Removing the N2 as it forms
B. Removing the NH3 as it forms
c. Decreasing the pressure
D. Increasing the temperature

Which change in this process would shift the equilibrium to produce the maximum possible NH3 3H2 N2 2 2NH3 energy A Removing the N2 as it forms B Removing the N class=

Respuesta :

Answer: B I think, I'll put my reasoning below.

Explanation:

It's not A because removing N2 would only shift the equation the opposite way.

It's not C and D because I don't think those affect the specific amount of each reactant/product produced. I think temperature only affects the speed at which the reaction is performed, which won't affect anything in this case.

Removing the ammonia as it forms is the correct answer to produce the maximum possible NH₃.

What is Haber's Process ?

It is an industrial process for manufacturing ammonia by reaction of nitrogen with hydrogen.

N₂+3H₂ ⇌ 2NH₃

The reaction is reversible and exothermic

To answer this question we will consider all the options and answer

Option D ) Increasing Temperature

Haber's process requires an optimal temperature of 450°C ,on Increasing temperature the yield of ammonia gets slow down.

Option C) Decreasing Pressure

Haber's Process requires high pressure to drive the reaction , higher the pressure more is the yield.

Option A ) Removing the N₂ as it forms , on removing  N₂ the reaction will drive on the reverse side hence low yield of NH₃ .

Option B) Removing the NH₃ as it forms , this can actually increase the yield as removing the ammonia will lead to shift the equilibrium and therefore increasing the yield.

Therefore Option B ,  Removing the ammonia (NH₃) as it forms is the correct answer to produce the maximum possible NH₃.

To know more about Haber's Process

https://brainly.com/question/26667299

#SPJ2