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A 4400 Kg Track Travelling at Intial speed 52m\s can be stopeed in 42 sec. By Gently Break, also the track can be stoped
in 7.6 m\s if the driver hit the wall.
a. What is the Impulse Excerted on the Vehicle?
b. Whta is the Averge force is exeted on the Track in each stops ?

Respuesta :

Answer:

(a) J = 10560  kg-m/s (b) 251.42 N

Explanation:

Given that,

Mass, m = 4400 kg

Initial speed, u = 5.2 m/s

Final speed, v = 7.6 m/s

Time, t = 42 s

(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :

J = m(v-u)

J = 4400 (7.6-5.2)

J = 10560  kg-m/s

(b) Impulse = Force × t

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{10560}{42}\\F=251.42\ N[/tex]

Hence, this is the required solution.

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