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One essential step in the manufacture of many plant fertilizers is the production of nitrogen monoxide gas, NO(g). This step is represented by the following balanced equation: 4 NH3(g) + 5 O2(g) --> 4 NO(g) + 6 H2O(l)
Determine the amount of oxygen needed to produce 1.2 x 104 mol of nitrogen monoxide gas.

Respuesta :

Answer: 1.5 moles, or 48 grams

Explanation:

Set up the following:

[tex]\frac{1.2 x 10^4 mol NO}{1}[/tex] × [tex]\frac{5 mol O2}{4 mol NO}[/tex] = 1.5 moles of O2 needed

If you're also looking for the number of grams needed:

[tex]\frac{1.5 mol}{1}[/tex] × [tex]\frac{32 g}{1 mol}[/tex] = 48 grams needed

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