Answer:
∆ABC ≅ ∆EDF by the SAS Congruence Theorem.
Step-by-step explanation:
<A ≅ <E,
Side length AC ≅ Side length EF
Side length AB ≅ Side length ED,
Thus, this implies that an included angle and two sides of one triangle are congruent to an included angle and 2 corresponding side lengths of the other triangle.
Therefore, we would conclude that:
∆ABC ≅ ∆EDF by the SAS Congruence Theorem.
