Answer:
∆ABE ≅ ∆DCE by SAS Congruence Theorem.
Step-by-step explanation:
The diagram given indicates the following:
<E ≅ <E (vertical angles)
AE ≅ DE
BE ≅ CE
Thus, an included angle, <E, and two side lengths, AE and BE, in ∆ABE are congruent to an included angle, <E, and two corresponding side lengths, DE and CE, in ∆DCE. By the SAS Congruence Theorem, both angles are congruent to each other.
Therefore:
∆ABE ≅ ∆DCE by SAS Congruence Theorem.
