Respuesta :

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Answer:

C. 8.80 mol H₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Moles

Stoichiometry

  • Using Dimensional Analysis
  • Analyzing Reactions RxN

Explanation:

Step 1: Define

[RxN - Balanced] N₂ (g) + 3H₂ (g) → 2NH₃ (g)

[Given] 100 g 2NH₃

[Solve] moles H₂

Step 2: Identify Conversions

[RxN] 2 mol NH₃ (g) → 3 mol H₂ (g)

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of NH₃ - 14.01 + 3(1.01) = 17.04 g/mol

Step 3: Stoich

  1. [DA] Set up conversion:                                                                                 [tex]\displaystyle 100 \ g \ NH_3(\frac{1 \ mol \ NH_3}{17.04 \ g \ NH_3})(\frac{3 \ mol \ H_2}{2 \ mol \ NH_3})[/tex]
  2. [DA] Multiply/Divide [Cancel out units]:                                                         [tex]\displaystyle 8.80282 \ mol \ H_2[/tex]

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