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Five times the sum of number and 27 is greater than or equal to six times the sum of that number and 26. What is the
solution set of this problem?

Respuesta :

Lanuel

Answer:

[tex] x \geq -21[/tex]

Step-by-step explanation:

Let the number be x.

Translating the word problem into an algebraic equation, we have;

[tex] 5(x + 27) \geq 6(x + 26) [/tex]

Opening the bracket, we have;

[tex] 5x + 135 \geq 6x + 156 [/tex]

Collecting like terms, we have;

[tex] 6x - 5x \geq 135 - 156 [/tex]

[tex] x \geq -21[/tex]

Answer:

B (-∞, -21]

Step-by-step explanation:

edge

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