Answer:
The correct answer is 2.33g of [tex]H_{2}O[/tex], A
Explanation:
We can use basic stoich to get this question.
To start, lets convert our grams to moles in order to use our equation. 5.38g of [tex]O_{2} = (\frac{5.38}{2*15.999}) moles = 0.168136[/tex] moles.
We then can use our molar ratio of 13:10. Simply divide by our molar ratio in order to go from moles of [tex]O_{2}[/tex] to moles of [tex]H_{2}O[/tex]. This gets us 0.129335 moles of [tex]H_{2}O[/tex].
Now lets convert to grams of [tex]H_{2}O[/tex] by multiplying by the molar mass of [tex]H_{2}O[/tex]. [tex].129335*(1.008*2+15.999) = 2.32997g[/tex] of [tex]H_{2}O[/tex]
