Answer:
–2733.4 KJ
Explanation:
The balanced equation for the reaction is given below:
C₂H₅OH + 3O₂ —> 2CO₂ + 3H₂O
ΔH = −1366.7 kJ
From the balanced equation above,
1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.
Finally, we shall determine the enthalpy change (ΔH) produced by the reaction of 2 moles of C₂H₅OH. This can be obtained as follow:
From the balanced equation above,
1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.
Therefore, 2 moles of C₂H₅OH will react to produce enthalpy change (ΔH) of = 2 × −1366.7 = –2733.4 KJ.
Thus, enthalpy change (ΔH) obtained is –2733.4 KJ
