Answer:
91.7 inches to 1 decimal place
Step-by-step explanation:
We will use Pythagoras's theorem to find the height of the pyramid.
The height of the Pyramid forms a right-angled triangle with half of the base and the slant height.
We can get half the length of the base by dividing the length of one side of the base = 20.4 by 2 = 10.2in
slant height = 92.3in
Therefore height = [tex]\sqrt{92.3^{2} -10.2^2} =91.73in[/tex]
The height of the pyramid is 91.73inches to 1 decimal place
